Python简单查询用户
一，第一种：
采用文件中contact.txt中第一行读出后，将其分割成列表，然后对其判断，但是不支持部门查询。
#!/usr/bin/env python
while True:
name=raw_input('please input name:')
if name == 'small':
while True:
password=raw_input('please input password:')
if password == '123':
print 'welcome login system'
while True:
input=raw_input('please input employee name:')
f=open('contact.txt','r')
match=0
for i in f.readlines():
if input == i.split(" ")[1]:
print i
match=1
if match==0:
print "user not found,please input"
f.close()
#break
else:
print 'password is wrong,try again'
break
第二种：将文件中每行读出后成字符串的形式，因此支持各个字段查询。
#!/usr/bin/python
while True:
input = raw_input("please input your username:")
if input == 'small':
password = raw_input("please input your pass:")
p = '123'
while password != p:
password = raw_input("wrong passwd,input again:")
else:
print "welcome login to linux!"
while True:
match_yes = 0
input = raw_input("\033[32mPlease input name whom you want to search:\33[0m")
contact_file = file('contact_list.txt','r')
while True:
line = contact_file.readline()
if len(line) == 0:break
if input != "" and input in line:
print "match item: \33{36,1m%s\033[0m" % line
match_yes = 1
if match_yes == 0 :print "no match item found"