js数组方法reduce经典用法代码分享(3)
片段十:数据加工器
const reducers = { totalInEuros: (state, item) => { return state.euros += item.price * 0.897424392; }, totalInYen: (state, item) => { return state.yens += item.price * 113.852; } }; const manageReducers = reducers => { return (state, item) => { return Object.keys(reducers).reduce((nextState, key) => { reducers[key](state, item); return state; }, {}) } } const bigTotalPriceReducer = manageReducers(reducers); const initialState = { euros: 0, yens: 0 }; const items = [{ price: 10 }, { price: 120 }, { price: 1000 }]; const totals = items.reduce(bigTotalPriceReducer, initialState);
片段十一:对象空值判断
let school = { name: 'Hope middle school', created: '2001', classes: [ { name: '三年二班', teachers: [ { name: '张二蛋', age: 26, sex: '男', actor: '班主任' }, { name: '王小妞', age: 23, sex: '女', actor: '英语老师' } ] }, { name: '明星班', teachers: [ { name: '欧阳娜娜', age: 29, sex: '女', actor: '班主任' }, { name: '李易峰', age: 28, sex: '男', actor: '体育老师' }, { name: '杨幂', age: 111, sex: '女', actor: '艺术老师' } ] } ] }; // 常规做法 school.classes && school.classes[0] && school.classes[0].teachers && school.classes[0].teachers[0] && school.classes[0].teachers[0].name // reduce方法 const get = (p, o) => p.reduce((xs, x) => (xs && xs[x] ? xs[x] : null), o); get(['classes', 0, 'teachers', 0, 'name'], school); // 张二蛋
片段十二:分组
const groupBy = (arr, func) => arr.map(typeof func === 'function' ? func : val => val[func]).reduce((acc, val, i) => { acc[val] = (acc[val] || []).concat(arr[i]); return acc; }, {}); groupBy([6.1, 4.2, 6.3], Math.floor); groupBy(['one', 'two', 'three'], 'length');
首先通过
map
计算出所有的键值,然后再根据建值进行归类片段十三:对象过滤
const pick = (obj, arr) =>
arr.reduce((acc, curr) => (curr in obj && (acc[curr] = obj[curr]), acc), {});pick({ a: 1, b: '2', c: 3 }, ['a', 'c']);
根据给出的键值来遍历,比较对象中是否存在相同键值的的值,然后通过逗号表达式把赋值后的对象赋给下一个的初始值