id 自动编号
pid 父ID
id_path 节点路径
flg 位置,0左边,1右边
ALTER PROCEDURE [dbo].[get_class]
复制代码 代码如下:
@class int,
@return int output
AS
SELECT @return=isnull(( select top 1 id from class where pid=@class and flg=0 ),-2)
if @return>-1
begin
exec get_class @return,@return output--这里为什么要用@return,你要最后得到这个值,必须把它传进去
end
else
begin
SELECT @return=@class
end
GO
@return int output
AS
SELECT @return=isnull(( select top 1 id from class where pid=@class and flg=0 ),-2)
if @return>-1
begin
exec get_class @return,@return output--这里为什么要用@return,你要最后得到这个值,必须把它传进去
end
else
begin
SELECT @return=@class
end
GO
其实只需一个查询语句就能找出最下面的ID
节点路径包函1,并且父节点位置都是左边,取出最大一个
select top 1 * from class a where id_path like '%1,%' and flg=0 and (select flg from class where id=a.pid)=0 order by id desc