这里只考虑最简单字符串的数组去重，暂不考虑，对象，函数，NaN等情况，这种用正则实现起来就吃力不讨好了。
非正则实现：ES6实现
<script> let str_arr=["b","c",1,"a", 3,"v", "2","e", "6","g", "9", "arr",9, "hello",",6", "9", "1", 2, 6, "b", "c"] function unique(arr){ return [...new Set(arr)] } console.log(unique(str_arr)) </script>
运行结果：
ES5实现
<script> var str_arr = ["b","c",1,"a", 3,"v", "2","e", "6","g", "9", "arr",9, "hello",",6", "9", "1", 2, 6, "b", "c"] function unique(arr) { return arr.filter(function(ele, index, array) { return array.indexOf(ele) === index }) } console.log(unique(str_arr)) </script>
运行结果同上
ES3实现
<script> var str_arr = ["b","c",1,"a", 3,"v", "2","e", "6","g", "9", "arr",9, "hello",",6", "9", "1", 2, 6, "b", "c"] function unique(arr) { var obj = {}, array = [] for (var i = 0, len = arr.length; i < len; i++) { var key = arr[i] + typeof arr[i] if (!obj[key]) { obj[key] = true array.push(arr[i]) } } return array } console.log(unique(str_arr)) </script>
运行结果同上
用正则实现
<script> var str_arr = ["b","c",1,"a", 3,"v", "2","e", "6","g", "9", "arr",9, "hello",",6", "9", "1", 2, 6, "b", "c"] function unique(arr) { return arr.sort().join(",,"). replace(/(,|^)([^,]+)(,,\2)+(,|$)/g, "$1$2$4"). replace(/,,+/g, ","). replace(/,$/, ""). split(",") } console.log(unique(str_arr)) </script>
运行结果：
感兴趣的朋友可以使用在线HTML/CSS/JavaScript代码运行工具：测试上述代码运行效果。
PS：这里再为大家提供几款相关工具供大家参考使用：
更多关于JavaScript相关内容还可查看本站专题：《JavaScript数组操作技巧总结》、《JavaScript字符与字符串操作技巧总结》、《JavaScript遍历算法与技巧总结》、《JavaScript查找算法技巧总结》、《JavaScript数学运算用法总结》、《JavaScript数据结构与算法技巧总结》及《JavaScript错误与调试技巧总结》