PHP编写学校网站上新生注册登陆程序的实例分享(2)

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=gb2312"> <title>基本信息</title> </head> <body background="image/bg6.jpg"> <?php if($_POST['log_name']=='') { echo "<center><font color='blue' size='8'><b>姓名不能为空!请重新输入!<br></b></font></center>"; echo "<center><font size='6'><a href='https://www.jb51.net/mysql_stu.php'>重新登录</font></center>"; } else { $link = mysql_connect('localhost','root','Dongsheng'); if(!$link) { echo "与数据库连接失败!"; die('Could not connect: ' .mysql_error()); } $result=mysql_select_db(mis_stu) or die('选择mis_stu数据库失败:'.mysql_error()); mysql_query("set names gb2312"); $slt=mysql_query("select * from stu_reg"); $arr=mysql_fetch_assoc($slt); $flag=0; while($arr) { if($_POST['log_name']==$arr['stu_name']) { $flag=1; if($_POST['log_id']==$arr['stu_id']) { echo "<font color='red' size='8'><b>登录成功,您的基本信息为:<br></b></font></center><br>"; echo "<font size='6'>姓名:".$arr['stu_name']."<br>"; echo "<font size='6'>性别:".$arr['stu_sex']."<br>"; echo "<font size='6'>年龄:".$arr['stu_age']."<br>"; echo "<font size='6'>班级:".$arr['stu_class']."<br>"; echo "<font size='6'>身份证号:".$arr['stu_id']."<br>"; echo "<font size='6'>联系电话:".$arr['stu_tele']."<br>"; echo "<font size='6'>电子邮件:".$arr['stu_email']."<br>"; break; } else { echo "<center><font color='blue' size='8'><b>密码错误!请<a href='https://www.jb51.net/mysql_stu.php'>重新输入。<br></b></font></center>"; break; } } $arr=mysql_fetch_assoc($slt); } if($flag==0) echo "<center><font color='blue' size='8'><b>对不起!您查询的用户不存在,请先返回<a href='https://www.jb51.net/register.php'>注册</a><br></b></font></center>"; mysql_close($link); echo "<center><font color='blue' size='6'><a href='https://www.jb51.net/mysql_stu.php'>切换用户</a><br></b></font></center>"; } ?> </body> </html>

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