php实现查询功能(数据访问)

php实现查询功能(数据访问)

输入关键字效果

php实现查询功能(数据访问)

代码:

<body> <h1>汽车信息</h1> <?php require"DBDA.class1.php";//$type 代表SQL语句的类型,0代表增删改,1代表查询 $db = new DBDA(); //如果没有提交数据,显示所有 //如果有提交数据,根据关键字查询显示 $name = ""; $tj1 = " 1=1 ";//第一个条件,对应名称,注意空格 $tj2 = " 1=1 ";//第二个条件,对应系列,注意空格 if(!empty($_POST["name"])) { $name = $_POST["name"]; $tj1 = " name like '%{$name}%'"; } if(!empty($_POST["brand"])) { $brand = $_POST["brand"]; $tj2 = " brand like '%{$brand}%'"; } //总条件 $tj ="{$tj1} and {$tj2}"; $sql = "select * from car where ".$tj;//注意where后空格 /*echo $sql;*/ ?> <form action="chaxun.php" method="post"> <div>名称:<input type="text" value="<?php echo $name ?>"/>系列:<input type="text"/><input type="submit" value="查询" /></div> </form> <br/> <table cellpadding="0" cellspacing="0"> <tr> <td>代号</td> <td>名称</td> <td>系列</td> <td>上市时间</td> <td>价格</td> </tr> <?php //只适用于单条件查询 /*$sql = "select * from car"; $name=""; if(!empty($_POST["name"])) { $name = $_POST["name"]; $sql = "select * from car where name like '%{$name}%' "; }*/ $arr = $db->query($sql); foreach($arr as $v) { $str = str_replace($name,"<span>{$name}</span>",$v[1]); echo "<tr> <td>{$v[0]}</td> <td>{$str}</td> <td>{$v[2]}</td> <td>{$v[3]}</td> <td>{$v[7]}</td> </tr>"; } ?> </table> </body> </html>

所引用的封装类

<?php class DBDA { public $host = "localhost"; public $uid = "root"; public $pwd = "123"; public $dbname = "newssystem"; //执行SQL语句返回相应的结果 //$sql 要执行的SQL语句 //$type 代表SQL语句的类型,0代表增删改,1代表查询 function query($sql,$type=1) { $db = new MySQLi($this->host,$this->uid,$this->pwd,$this->dbname); $result = $db->query($sql); if($type) { //如果是查询,显示数据 return $result->fetch_all(); } else { //如果是增删改,返回true或者false return $result; } } }

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