SQL> select t2.locality,t1.index_name,t1.partition_name,t1.status,t1.tablespace_name from user_ind_partitions t1, user_part_indexes t2 where t1.index_name in ('IND_JSSJ01') and t1.index_name=t2.index_name
2 order by index_name,partition_name;
LOCALI INDEX_NAME PARTITION_NAME STATUS TABLESPACE_NAME
------ ------------------------------ ------------------------------ -------- ------------------------------
LOCAL IND_JSSJ01 P01 USABLE USERS
LOCAL IND_JSSJ01 P03 USABLE USERS
LOCAL IND_JSSJ01 P04 USABLE USERS
LOCAL IND_JSSJ01 P05 USABLE USERS
--结论 本地分区索引,删除某个分区 对于其他的索引分区没有任何影响