检测逻辑:连续3次访问tomcat提供的接口,若3次响应码都不为200,则自动重启tomcat
脚本内容:
#!/bin/bash
source /etc/profile
IP=10.78.1.183
PORT=8114
TOMCAT_DIR=/soft/tomcat_8114
#定义发送邮件函数
function send_mail(){
maillist=(
linuxidc@linuxidc.com
)
DATE=`date +'%F %T'`
SUBJECT="${IP}的${PORT}端口发生故障,已自动重启!"
CONTENT="时间:${DATE}\n主机:${IP}\n事件:${PORT}端口发生重启"
for mail in ${maillist[*]};do
echo -e "${CONTENT}" | mail -s "${SUBJECT}" $mail
done
}
#对接口访问3次
declare -i NUM=0
for i in `seq 1 3`;do
CODE=$(/usr/bin/curl -I -m 10 -o /dev/null -s -w %{http_code}"\n" ${IP}:${PORT})
if [ $CODE == "000" ];then
((NUM++))
fi
sleep 3
done
#根据NUM的值来确定是否重启tomcat,NUM=3时进行重启
if [ $NUM == 3 ];then
IS_LIVING=`jps -m -l -v | grep "${PORT}" | wc -l`
if [ ${IS_LIVING} -eq 1 ];then
PID=`jps -m -l -v | grep "${PORT}" | awk '{print $1}'`
kill -9 $PID
${TOMCAT_DIR}/bin/startup.sh
elif [ ${IS_LIVING} -eq 0 ];then
${TOMCAT_DIR}/bin/startup.sh
fi
send_mail
fi
任务计划:每5分钟检测一次
*/5 * * * * /server/scripts/tomcat/check_8114.sh &> /dev/null
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