Oracle exists/in和not exists/not in之前的区别与联系

曾写过一篇关于Oracle NULL对in和not in结果的影响:Oracle的where条件in/not in中包含NULL时的处理。今天来看看exists和not exists中NULL值对结果的影响。

网上经常看到关于in和exixts、not in和not exists性能比对和互换的例子,但它们真的就可以简单互换么?我们通过下面的实验来看一下。
实验环境:Oracle 11.2.0.4

1、创建表并插入测试数据

create table t1 (id number);
create table t2 (id number);
insert into t1 values(1);
insert into t1 values(2);
insert into t1 values(3);
insert into t1 values(4);
insert into t1 values(null);
commit;
insert into t2 values(3);
insert into t2 values(4);
insert into t2 values(5);
insert into t2 values(6);
commit;
linuxidc@ORA11G>select * from t1;
 
    ID
----------
    1
    2
    3
    4
 
 
5 rows selected. 
 
linuxidc@ORA11G>select * from t2;
 
    ID
----------
    3
    4
    5
    6
 
4 rows selected.

第一种情况:exists/in的查询中不包含NULL,外层查询包含NULL
linuxidc@ORA11G>select * from t1 where exists(select 1 from t2 where t1.id=t2.id);
 
    ID
----------
    3
    4
 
2 rows selected. 
 
linuxidc@ORA11G>select * from t1 where id in (select id from t2);
 
    ID
----------
    3
    4
 
2 rows selected.

从上面的查询结果看出exists和in都查到了id=2和3的两条数据。
第二种情况:not exists/not in的查询中不包含NULL,外层查询包含NULL
linuxidc@ORA11G>select * from t1 where not exists(select 1 from t2 where t1.id=t2.id);
 
    ID
----------
 
    1
    2
 
3 rows selected. 
 
linuxidc@ORA11G>select * from t1 where id not in (select id from t2);
 
    ID
----------
    1
    2
 
2 rows selected.

从上面的结果中可以看到两个查询都查到了id=1和2这两条记录,但not exists还查到了t1表中id为NULL的行。原因是表t1中id为NULL的行exists(3,4,5,6)为False,但前面加了个not则返回结果就为True了。
第三种情况:exists/in的子查询中包含NULL,外层查询包含NULL
linuxidc@ORA11G>insert into t2 values(null);
 
1 row created. 
 
linuxidc@ORA11G>commit;
 
Commit complete. 
 
linuxidc@ORA11G>select * from t1 where id in (select id from t2);
 
    ID
----------
    3
    4
 
2 rows selected. 
 
linuxidc@ORA11G>select * from t1 where exists(select 1 from t2 where t1.id=t2.id);
 
    ID
----------
    3
    4
 
2 rows selected.

从上面的结果中可以看出exist和in的结果是一致的。
第四种情况:not exists和not in的查询中包含NULL
linuxidc@ORA11G>select * from t1 where not exists(select 1 from t2 where t1.id=t2.id);
 
    ID
----------
 
    1
    2
 
3 rows selected. 
 
linuxidc@ORA11G>select * from t1 where id not in (select id from t2);
 
no rows selected

从上面的查询结果中可以看出两个结果差异很大,not exists把id=1和2和为NULL的值都查出来了,而not in查出来的结果为空。no in结果为空的原因可以参考之前的文章,not exists的原因与第二种情况类似。
第五种情况:not in/not exists的子查询中无NULL值,外层查询也无NULL值
linuxidc@ORA11G>delete from t1 where id is null;
 
1 row deleted. 
 
linuxidc@ORA11G>delete from t2 where id is null;
 
1 row deleted. 
 
linuxidc@ORA11G>commit;
 
Commit complete. 
 
linuxidc@ORA11G>select * from t1 where id not in (select id from t2);
 
    ID
----------
    1
    2
 
2 rows selected. 
 
linuxidc@ORA11G>select * from t1 where not exists(select 1 from t2 where t1.id=t2.id);
 
    ID
----------
    1
    2
 
2 rows selected.

内容版权声明:除非注明,否则皆为本站原创文章。

转载注明出处:https://www.heiqu.com/836c0a0d71cf73c3508574f3b4868dfa.html