题目:输入一棵二叉搜索树,现在要将该二叉搜索树转换成一个排序的双向链表。而且在转换的过程中,不能创建任何新的结点,只能调整树中的结点指针的指向来实现。
思路:采用中序遍历将二叉树从小到大遍历每一个结点,通过改变指针来实现双向链表。
#include<stdio.h>
#include "stdafx.h"
#include<tchar.h>
struct BinaryTreeNode
{
int m_nValue;
BinaryTreeNode* m_pLeft;
BinaryTreeNode* m_pRight;
};
BinaryTreeNode* CreateBinaryTreeNode(int value)
{
BinaryTreeNode* pNode = new BinaryTreeNode();
pNode->m_nValue = value;
pNode->m_pLeft = NULL;
pNode->m_pRight = NULL;
}
void ConnectTreeNodes(BinaryTreeNode* pParent, BinaryTreeNode* pLeft, BinaryTreeNode* pRight)
{
if(pParent != NULL)
{
pParent->m_pLeft = pLeft;
pParent->m_pRight = pRight;
}
}
void PrintTreeNode(BinaryTreeNode* pNode)
{
if(pNode != NULL)
{
printf("value of this node is: %d\n", pNode->m_nValue);
if(pNode->m_pLeft != NULL)
printf("value of its left child is: %d.\n", pNode->m_pLeft->m_nValue);
else
printf("left child is null.\n");
if(pNode->m_pRight != NULL)
printf("value of its right child is: %d.\n",pNode->m_pRight->m_nValue);
else
printf("right child is null.\n");
}
else
{
printf("this node is null.\n");
}
printf("\n");
}
void PrintTree(BinaryTreeNode* pRoot)
{
PrintTreeNode(pRoot);
if(pRoot != NULL)
{
if(pRoot->m_pLeft != NULL)
PrintTree(pRoot->m_pLeft);
if(pRoot->m_pRight != NULL)
PrintTree(pRoot->m_pRight);
}
}
void DestroyTree(BinaryTreeNode* pRoot)
{
if(pRoot != NULL)
{
BinaryTreeNode* pLeft = pRoot->m_pLeft;
BinaryTreeNode* pRight = pRoot->m_pRight;
delete pRoot;
pRoot = NULL;
DestroyTree(pLeft);
DestroyTree(pRight);
}
}
void ConvertNode(BinaryTreeNode* pNode, BinaryTreeNode** pLastNodeInList);
BinaryTreeNode* Convert(BinaryTreeNode* pRootOfTree)
{
BinaryTreeNode *pLastNodeInList = NULL;
ConvertNode(pRootOfTree, &pLastNodeInList);
//pLastNodeInList指向链表的的尾结点,遍历找到头结点返回。
BinaryTreeNode *pHeadOfList = pLastNodeInList;
while(pHeadOfList != NULL && pHeadOfList->m_pLeft != NULL)
pHeadOfList = pHeadOfList->m_pLeft;
return pHeadOfList;
}
//中序遍历转换过程,
//参数:处理当前结点, 当前链表最后一个结点(初始值为空)
void ConvertNode(BinaryTreeNode* pNode, BinaryTreeNode** pLastNodeInList)
{
if(pNode == NULL)
return;
BinaryTreeNode *pCurrent = pNode;
//递归处理左子树
if(pCurrent->m_pLeft != NULL)
ConvertNode(pCurrent->m_pLeft, pLastNodeInList);
//将当前链表的左指针指向已经转换好的链表的最后一个位置
pCurrent->m_pLeft = *pLastNodeInList;
//将已经转换好的链表的最后一个结点的右指针指向当前结点
if(*pLastNodeInList != NULL)
(*pLastNodeInList)->m_pRight = pCurrent;
//更新链表最后一个结点
*pLastNodeInList = pCurrent;
//递归处理当前结点的右子树
if(pCurrent->m_pRight != NULL)
ConvertNode(pCurrent->m_pRight, pLastNodeInList);
}