javascript JSON操作入门实例(2)

private void doService(HttpServletRequest request, HttpServletResponse response) throws IOException {
String s3 = request.getParameter("car");
try {
JSONObject jsonObj = new JSONObject(s3);
System.out.println(jsonObj.getString("model"));
System.out.println(jsonObj.getInt("year"));
} catch (JSONException e) {
e.printStackTrace();
}
JSONObject resultJSON = new JSONObject();
try {
resultJSON.append("name", "Violet")
.append("occupation", "developer")
.append("age", new Integer(22));
System.out.println(resultJSON.toString());
} catch (JSONException e) {
e.printStackTrace();
}
response.getWriter().print(resultJSON.toString());
}
    

复制代码 代码如下:

function jsonResponse(originalRequest) {
alert(originalRequest.responseText);
var myobj = originalRequest.responseText.evalJSON(true);
alert(myobj.name);
alert(myobj.age);
}

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