// 拐一次弯搜索
isReach1 : function(piece) {
//alert("isReach1");
var corner_1 = this.game.pieceMap.get(this.x + "," + piece.y);
var corner_2 = this.game.pieceMap.get(piece.x + "," + this.y);
var _this = this;
if ((_this.isStraightReach(corner_1))
&& (corner_1.isStraightReach(piece))
&& corner_1.isPass()) {
//alert("corner_1: " + this.x + "," + piece.y);
this.game.trackList.push(corner_1);
return true;
}
if ((_this.isStraightReach(corner_2))
&& (corner_2.isStraightReach(piece))
&& corner_2.isPass()) {
//alert("corner_2: " + piece.x + "," + this.y);
this.game.trackList.push(corner_2);
return true;
}
return false;
},
在拐一次弯搜索的函数中调用了直接搜索的函数，同样最复杂的拐两次弯搜索也会调用拐一次弯搜索的函数。
复制代码 代码如下: