ajax实现点击不同的链接让返回的内容显示在特定

/* 以下代码通过ajax实现在一个web页面点击不同的链接,然后将返回的结果显示在该页面固定的div里。 */

<html> <head> <meta charset="UTF-8"> <title>Insert title here</title> <script language="javascript"> var http_request = false; function createRequest(url,objID){ http_request = false; if(window.XMLHttpRequest){ //非IE浏览器 http_request = new XMLHttpRequest(); if(http_request.overrideMimeType){ http_request.overrideMimeType("text/xml"); } }else if(window.ActiveXObject){ //IE浏览器 try{ http_request = new ActiveXObject("Msxml2.XMLHTTP"); }catch(e){ try{ http_request = new ActiveXObject("Microsoft.XMLHTTP"); }catch(e){} } } if(!http_request){ alert("无法创建XMLHTTP实例"); return false; } http_request.open("GET",url,true); http_request.send(null); var obj = document.getElementById(objID); http_request.onreadystatechange = function(){ if(http_request.readyState == 4){ if(http_request.status == 200){ obj.innerHTML = http_request.responseText; }else{ alert('您请求的页面发现错误!'); } } } } </script> </head> <body> <div> <a href="https://www.jb51.net/content1.html">no1</a> | <a href="https://www.jb51.net/content2.html">no2</a> | <a href="https://www.jb51.net/content3.html">no3</a> </div> <div></div> </body> </html>

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