JavaScript编写连连看小游戏(2)

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <title> 连连看 </title> <meta content="EditPlus"> <meta content=""> <meta content=""> <meta content=""> <style type="text/css"> #board{width:508px; height:500px; margin: 30px auto 0px; overflow: hidden; position: relative; background-color: #999999;} #board span{display: block; position: absolute; width: 30px; height: 30px; } </style> </head> <body> <div > </div> </body> <!-- js --> <script src="https://cdn.bootcss.com/jquery/2.1.4/jquery.min.js"></script> <script type="text/javascript" > $(function(){ var cont=$("#board"); var colors=["#ff0000","#00ff00","#0000ff","#ffcc33","#000000","#00ffcc","#ffffff"]; var pos=[]; var click=0; var firstSpan; var fx; var fy; var arr=[]; arr=[0,0,0,0,0,0,0,0]; pos.push(arr); for(var i=0;i<8;i++){ new creSpan(i,cont,0,i*40,colors[6],0); } for(var i=1;i<=6;i++){ m=new creSpan(i,cont,i*40,0,"#ffffff"); arr=[0]; for(var j=0;j<6;j++){ var color=Math.floor(Math.random()*6); new creSpan(i,cont,i*40,(j+1)*40,colors[color],(color+1)); arr.push(1); } m=new creSpan(i,cont,i*40,(j+1)*40,"#ffffff",0); arr.push(0); pos.push(arr); } for(var i=0;i<8;i++){ m=new creSpan(i,cont,7*40,i*40,"#ffffff",0); } arr=[0,0,0,0,0,0,0,0]; pos.push(arr); function clear(c1,c2,x,y){ if(c1!=null)c1.style.background="#ffffff"; if(c2!=null){ c2.style.background="#ffffff"; pos[x-1][y-1]=0; pos[fx-1][fy-1]=0; } fx=0; fy=0; click=0; } $.each($("#board span"),function(index,mSpan){ $(this).click(function(){ var x=Math.floor(index/8); var y=Math.floor(index%8); if(click==0){ click=1; firstSpan=mSpan; fx=x; fy=y; return; } if(firstSpan.id!=mSpan.id||(x==fx&&fy==y)){ clear(null,null,0,0); return; } var col=6; var row=6; for(var i=0;i<row+2;i++){ var step=i-x>0?1:-1; var count=0; for(var j=x;j!=i;j+=step){ count+=pos[j][y]; } step=y>fy?-1:1; for(j=y;j!=fy;j+=step){ count+=pos[i][j]; } step=i>fx?-1:1; for(j=i;j!=fx;j+=step){ count+=pos[j][fy]; } if(count==1){ clear(firstSpan,mSpan,x,y); return; } } for(i=0;i<col+2;i++){ step=i-y>0?1:-1; count=0; for(j=y;j!=i;j+=step){ count+=pos[x][j]; } step=x>fx?-1:1; for(j=x;j!=fx;j+=step){ count+=pos[i][j]; } step=i<fy?1:-1; for(j=i;j!=fy;j+=step){ count+=pos[fx][j]; } if(count==1){ clear(firstSpan,mSpan,x,y); return; } } clear(null,null,0,0); }); }); }); function creSpan(n,cont,mtop,mleft,mcolor,idstr){ var mSpan=document.createElement("span"); cont[0].appendChild(mSpan); mSpan.id=idstr; with(mSpan.style){ top=mtop+"px"; left=mleft+"px"; background=mcolor; } }; </script> </html>

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