通过构造AJAX参数实现表单元素JSON相互转换

ajax提交服务器数据， 整理一下转换方法。

HTML：

<form action=""> <input type="text" value="UserName1"/> </form> <input type="text" value="UserId1"/>

1.表单元素转QueryString

var q = $('#fm,#UserId').serialize(); //q = UserName=UserName1&UserId=UserId1

2.字符串， JSON 互相转换

var obj = jQuery.parseJSON('{"name":"John"}'); alert( obj.name === "John" );

可以利用jquery-json插件实现转换，直接引用示例

var thing = {plugin: 'jquery-json', version: 2.3}; var encoded = $.toJSON( thing ); // '{"plugin":"jquery-json","version":2.3}' var name = $.evalJSON( encoded ).plugin; // "jquery-json" var version = $.evalJSON(encoded).version; // 2.3

3.表单，元素转Name,Value数组

var arr = $("#fm,#UserId").serializeArray(); /*[ {name: 'UserName', value: '"UserName"1'}, {name: 'UserId', value: 'UserId'} ] */

4. 表单元素转JSON

$.fn.serializeObject = function() { var o = {}; var a = this.serializeArray(); $.each(a, function() { if (o[this.name] !== undefined) { if (!o[this.name].push) { o[this.name] = [o[this.name]]; } o[this.name].push(this.value || ''); } else { o[this.name] = this.value || ''; } }); return o; }; var obj = $('form').serializeObject(); /*obj: Object UserId: "UserId1" UserName: "UserName1" __proto__: Object*/

5. JSON2FORM

$.getJSON('url_to_file', function(data) { for (var i in data) { $('input[name="'+i+'"]').val(data[i]); } }

Google过程中发现一个更强大的插件

data = { "Name":"Emkay Entertainments", "Address":"Nobel House, Regent Centre", "Contact":"Phone" } $('div#data').loadJSON(data); <div> <h1>Emkay Entertainments</h1> <label for="Address">Address:</label> <span>Nobel House, Regent Centre</span> <label for="Contact">Contact by:</label> <span>Phone</span> </div>

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