Javascript 实现的数独解题算法网页实例(6)

for (var k = 0; k < 11; k++)
                {    candidatNum[i][j][k]=0;
        }
        }
    }
}
function choose() {
    //目标:
    //    遍历矩阵,从当前位置建立搜索分支.
    var binarynode = false;
    for (var i = 0; i < 9; i++) {
        for (var j = 0; j < 9; j++) {
    //      2叉树分支:
    //      如果在某位置有两种可能,选项1/选项2
    //      则假设是选项1,并进行验算,同时按选项2生成一个新的标签
            if (candidatNum[i][j][0] == 2) {// 有2种选择
                binarynode = true;
                var found = -1;
                for (var k = 1; k < 10; k++) {
                    if  ((candidatNum[i][j][1] & (1 << k)) > 0) {
                        if (found > 0) {
                            papers ++;
                            var timeline = document.getElementById('PaperList');
                            timeline.value += ('add papers:'+papers+':'+i+' '+j+' '+k+'\n');
                            timeline.scrollTop = timeline.scrollHeight;
                            push(grid, i, j, k);
                        }else{
                            found = k;
                        }
                    }
                }
                grid[i][j] = found;
                candidatNum[i][j][0] = 0; // 在当前标签上标记已选
                            var timeline = document.getElementById('PaperList');
                            timeline.value += ('TRY CURRENT:'+i+' '+j+' '+found+'\n');
                            timeline.scrollTop = timeline.scrollHeight;
                return true;
            }
        }
    }
    if (!binarynode) {
    var timeline = document.getElementById('PaperList');
    timeline.value += ('2叉分支未找到!\n');
    timeline.scrollTop = timeline.scrollHeight;
        for (var i = 0; i < 9; i++) {
            for (var j = 0; j < 9; j++) {
        // 2叉树查找失败时，启动3叉树分支，作为扩充，还可以启动3叉树分支：
        //      如果在某位置有三种可能,选项1/选项2/选项3
        //      则假设是选项1,并进行验算,同时按选项2生成一个新的标签
                if (candidatNum[i][j][0] == 3) {// 有3种选择
                            var timeline = document.getElementById('PaperList');
                            timeline.value += ('发现3叉分支!\n');
                            timeline.scrollTop = timeline.scrollHeight;
                    binarynode = true;
                    var found = -1;
                    for (var k = 1; k < 10; k++) {
                        if  ((candidatNum[i][j][1] & (1 << k)) > 0) {
                            if (found > 0) {
                                papers ++;
                            var timeline = document.getElementById('PaperList');
                            timeline.value += ('add papers:'+papers+':'+i+' '+j+' '+k+'\n');
                            timeline.scrollTop = timeline.scrollHeight;
                                push(grid, i, j, k);
                            }else{
                                found = k;
                            }
                        }
                    }
                    grid[i][j] = found;
                    candidatNum[i][j][0] = 0; // 在当前标签上标记已选
                            var timeline = document.getElementById('PaperList');
                            timeline.value += ('TRY CURRENT:'+i+' '+j+' '+found+'\n');
                            timeline.scrollTop = timeline.scrollHeight;
                    return true;
                }
            }
        }
    }
    return false;
}
function paste(){
    var gridstr= document.getElementById("gtxt").value;
    var a = gridstr.replace(/[^0-9]/g,'');
    if(a.length!=81){
       alert("数据格式不正确:\n"+gridstr);
       return;
    }
    for (var i = 0; i < 9; i++)
        {
            for (var j = 0; j < 9; j++){
                grid[i][j]=a.charAt(i*9+j);
                document.getElementById("input"+(i*9+j)).value=grid[i][j];
        }
    }
    out(grid);
    papers = 0;
    discards = 0;
    success = false;
    steps = new Array();
}
  </script>
  建议使用IE浏览器,F12开启调试模式<br>
<br><span>
<textarea cols="30" rows="20"></textarea></span>
 </body>
</html>

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