根据 Id 查询也没有问题。
Hibernate: select user0_.id as id1_0_0_, user0_.age as age2_0_0_, user0_.birthday as birthday3_0_0_, user0_.password as password4_0_0_, user0_.skills as skills5_0_0_, user0_.username as username6_0_0_ from user user0_ where user0_.id=? User(id=1, username=Darcy, password=123, age=18, birthday=2019-01-12 21:02:30.0, skills=Go)更新操作也是正常输出 SQL ，没有任何异常。
Hibernate: select user0_.id as id1_0_0_, user0_.age as age2_0_0_, user0_.birthday as birthday3_0_0_, user0_.password as password4_0_0_, user0_.skills as skills5_0_0_, user0_.username as username6_0_0_ from user user0_ where user0_.id=? 18 Hibernate: select user0_.id as id1_0_0_, user0_.age as age2_0_0_, user0_.birthday as birthday3_0_0_, user0_.password as password4_0_0_, user0_.skills as skills5_0_0_, user0_.username as username6_0_0_ from user user0_ where user0_.id=? Hibernate: update user set age=?, birthday=?, password=?, skills=?, username=? where id=?最后一个是自定义查询操作，上面三个方法的输出中，Darcy 用户对应的年龄是 18，在经过更新加1 之后应该变为19，下面是自定义查询的结果。
Hibernate: select user0_.id as id1_0_, user0_.age as age2_0_, user0_.birthday as birthday3_0_, user0_.password as password4_0_, user0_.skills as skills5_0_, user0_.username as username6_0_ from user user0_ where user0_.username=? and user0_.password=? User(id=1, username=Darcy, password=123, age=19, birthday=2019-01-12 21:02:30.0, skills=Go)可见是没有任何问题的。
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