Step 9. ActivityStack.startActivityUncheckedLocked
这个函数定义在frameworks/base/services/java/com/Android/server/am/ActivityStack.java文件中：
public class ActivityStack { ...... final int startActivityUncheckedLocked(ActivityRecord r, ActivityRecord sourceRecord, Uri[] grantedUriPermissions, int grantedMode, boolean onlyIfNeeded, boolean doResume) { final Intent intent = r.intent; final int callingUid = r.launchedFromUid; int launchFlags = intent.getFlags(); // We'll invoke onUserLeaving before onPause only if the launching // activity did not explicitly state that this is an automated launch. mUserLeaving = (launchFlags&Intent.FLAG_ACTIVITY_NO_USER_ACTION) == 0; ...... ActivityRecord notTop = (launchFlags&Intent.FLAG_ACTIVITY_PREVIOUS_IS_TOP) != 0 ? r : null; // If the onlyIfNeeded flag is set, then we can do this if the activity // being launched is the same as the one making the call... or, as // a special case, if we do not know the caller then we count the // current top activity as the caller. if (onlyIfNeeded) { ...... } if (sourceRecord == null) { ...... } else if (sourceRecord.launchMode == ActivityInfo.LAUNCH_SINGLE_INSTANCE) { ...... } else if (r.launchMode == ActivityInfo.LAUNCH_SINGLE_INSTANCE || r.launchMode == ActivityInfo.LAUNCH_SINGLE_TASK) { ...... } if (r.resultTo != null && (launchFlags&Intent.FLAG_ACTIVITY_NEW_TASK) != 0) { ...... } boolean addingToTask = false; if (((launchFlags&Intent.FLAG_ACTIVITY_NEW_TASK) != 0 && (launchFlags&Intent.FLAG_ACTIVITY_MULTIPLE_TASK) == 0) || r.launchMode == ActivityInfo.LAUNCH_SINGLE_TASK || r.launchMode == ActivityInfo.LAUNCH_SINGLE_INSTANCE) { // If bring to front is requested, and no result is requested, and // we can find a task that was started with this same // component, then instead of launching bring that one to the front. if (r.resultTo == null) { // See if there is a task to bring to the front. If this is // a SINGLE_INSTANCE activity, there can be one and only one // instance of it in the history, and it is always in its own // unique task, so we do a special search. ActivityRecord taskTop = r.launchMode != ActivityInfo.LAUNCH_SINGLE_INSTANCE ? findTaskLocked(intent, r.info) : findActivityLocked(intent, r.info); if (taskTop != null) { ...... } } } ...... if (r.packageName != null) { // If the activity being launched is the same as the one currently // at the top, then we need to check if it should only be launched // once. ActivityRecord top = topRunningNonDelayedActivityLocked(notTop); if (top != null && r.resultTo == null) { if (top.realActivity.equals(r.realActivity)) { ...... } } } else { ...... } boolean newTask = false; // Should this be considered a new task? if (r.resultTo == null && !addingToTask && (launchFlags&Intent.FLAG_ACTIVITY_NEW_TASK) != 0) { // todo: should do better management of integers. mService.mCurTask++; if (mService.mCurTask <= 0) { mService.mCurTask = 1; } r.task = new TaskRecord(mService.mCurTask, r.info, intent, (r.info.flags&ActivityInfo.FLAG_CLEAR_TASK_ON_LAUNCH) != 0); ...... newTask = true; if (mMainStack) { mService.addRecentTaskLocked(r.task); } } else if (sourceRecord != null) { ...... } else { ...... } ...... startActivityLocked(r, newTask, doResume); return START_SUCCESS; } ...... }
函数首先获得intent的标志值，保存在launchFlags变量中。这个intent的标志值的位Intent.FLAG_ACTIVITY_NO_USER_ACTION没有置位，因此 ，成员变量mUserLeaving的值为true。
这个intent的标志值的位Intent.FLAG_ACTIVITY_PREVIOUS_IS_TOP也没有置位，因此，变量notTop的值为null。