JAVA 18位身份证号码校验码的算法

public static char doVerify(String id)
{
char pszSrc[]=id.toCharArray();
int iS = 0;
int iW[]={7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2};
char szVerCode[] = new char[]{'1','0', 'X', '9', '8', '7', '6', '5', '4', '3', '2'};
int i;
for(i=0;i<17;i++)
{
iS += (int)(pszSrc[i]-'0') * iW[i];
}
int iY = iS%11;
return szVerCode[iY];
}

您可能感兴趣的文章:

内容版权声明:除非注明,否则皆为本站原创文章。

转载注明出处:https://www.heiqu.com/wzfpgg.html