再谈Jquery Ajax方法传递到action(补充)

复制代码 代码如下:

public ActionResult ReadPerson(PersonModel model) 
        { 
            string s = model.ToString(); 
            return Content(s); 
        }

public ActionResult ReadPersons(List<PersonModel> model) 
        { 
            string result = ""; 
            if (model == null) return Content(result); 
            foreach (var s in model) 
            { 
                result += s.ToString(); 
                result += "-------------"; 
            }
            return Content(result); 
        }

其中PersonModel定义如下：

复制代码 代码如下:

public class PersonModel 
    { 
        public int id 
        { 
            set; 
            get; 
        } 
        public string name 
        { 
            set; 
            get; 
        }

public int age 
        { 
            set; 
            get; 
        }

public bool gender 
        { 
            set; 
            get; 
        } 
        public string city 
        { 
            set; 
            get; 
        }

public override string ToString() 
        { 
            string s = string.Format(@"id:{0} 
name:{1} 
age:{2} 
gender:{3} 
city:{4} 
", id, name, age, gender, city); 
            return s; 
        } 
    }

那么controller方法分别接受单个model和一个model的List。采用通过ajax传递参数。
对于传递单个参数的情况,假设js代码如下：

复制代码 代码如下:

var person = { 
               id: "001", 
               name: "zhangsan", 
               age: "20", 
               gender: true, 
               city: "shanghai" 
           };

var option = { 
               url: '/test/ReadPerson', 
               type: 'POST', 
               data: person, 
               dataType: 'html', 
               success: function (result) { alert(result); } 
           }; 
$.ajax(option);