当时给出的解决方案是实现kk_modelValue或者kk_didConvertToModel方法，根据实际需求自定义JSON的解析逻辑
如果不确定的内容是要转成模型，KakaJSON有更简单的实现方案
举例 struct Book: Convertible { var name: String = "" var price: Double = 0.0 } struct Car: Convertible { var name: String = "" var price: Double = 0.0 } struct Pig: Convertible { var name: String = "" var height: Double = 0.0 } struct Dog: Convertible { var name: String = "" var weight: Double = 0.0 } struct Person: Convertible { var name: String = "" var pet: Any? // 这里用`NSArray`、`NSMutableArray`也行 var toys: [Any]? // 这里用`NSDictionary`、`NSMutableDictionary`也行 var foods: [String: Any]? func kk_modelType(from jsonValue: Any?, property: Property) -> Convertible.Type? { switch property.name { case "toys": return Car.self // `toys`数组存放`Car`模型 case "foods": return Book.self // `foods`字典存放`Book`模型 case "pet": if let pet = jsonValue as? [String: Any], let _ = pet["height"] { // 如果`pet`属性的`jsonValue`是个字典，并且有`height`这个key，就转为`Pig`模型 return Pig.self } // 将`jsonValue`转为`Dog`模型赋值给`pet`属性 return Dog.self default: return nil } } } // 测试数据 let name = "Jack" let dog = (name: "Wang", weight: 109.5) let pig = (name: "Keke", height: 1.55) let books = [ (name: "Fast C++", price: 666.0), (name: "Data Structure And Algorithm", price: 1666.0) ] let cars = [ (name: "Benz", price: 100.5), (name: "Bently", price: 300.6) ] // JSON数据 let json: [String: Any] = [ "name": name, "pet": ["name": dog.name, "weight": dog.weight], // "pet": ["name": pig.name, "height": pig.height], "toys": [ ["name": cars[0].name, "price": cars[0].price], ["name": cars[1].name, "price": cars[1].price] ], "foods": [ "food0": ["name": books[0].name, "price": books[0].price], "food1": ["name": books[1].name, "price": books[1].price] ] ] let person = json.kk.model(Person.self) XCTAssert(person?.name == name) if let pet = person?.pet as? Dog { XCTAssert(pet.name == dog.name) XCTAssert(pet.weight == dog.weight) } else if let pet = person?.pet as? Pig { XCTAssert(pet.name == pig.name) XCTAssert(pet.height == pig.height) } let toy0 = person?.toys?[0] as? Car XCTAssert(toy0?.name == cars[0].name) XCTAssert(toy0?.price == cars[0].price) let toy1 = person?.toys?[1] as? Car XCTAssert(toy1?.name == cars[1].name) XCTAssert(toy1?.price == cars[1].price) let food0 = person?.foods?["food0"] as? Book XCTAssert(food0?.name == books[0].name) XCTAssert(food0?.price == books[0].price) let food1 = person?.foods?["food1"] as? Book XCTAssert(food1?.name == books[1].name) XCTAssert(food1?.price == books[1].price)