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可用于加密SQL存储过程或者触发器
（这是SQL Server本身提供的，也就是说这是微软的加密算法）
使用 WITH ENCRYPTION 选项
WITH ENCRYPTION 子句对用户隐藏存储过程的文本。下例创建加密过程，使用 sp_helptext 系统存储过程获取关于加密过程的信息，然后尝试直接从 syscomments 表中获取关于该过程的信息。
IF EXISTS (Select name FROM sysobjects
Where name = 'encrypt_this' AND type = 'P')
Drop PROCEDURE encrypt_this
GO
USE pubs
GO
Create PROCEDURE encrypt_this
WITH ENCRYPTION
AS
Select *
FROM authors
GO
EXEC sp_helptext encrypt_this
下面是结果集：
The object's comments have been encrypted.
接下来，选择加密存储过程内容的标识号和文本。
Select c.id, c.text
FROM syscomments c INNER JOIN sysobjects o
ON c.id = o.id
Where o.name = 'encrypt_this'
下面是结果集：
说明 text 列的输出显示在单独一行中。执行时，该信息将与 id 列信息出现在同一行中。
Id text
---------- ------------------------------------------------------------
1413580074 ?????????????????????????????????e??????????????????????????????????????????????????????????????????????????
(1 row(s) affected)
备注：
create proc name
with encryption
as
begin
--语句
end
Create TRIGGER trigger_name
ON { table | view }
WITH ENCRYPTION
FOR Update
AS
begin
--语句
end
Sql存储过程解密算法 破解微软的加密算法
网上同样有很多的Sql存储过程的解密软件，但大都是收费的。
下边是网上流传的Sql存储过程解密算法，虽非官方，但绝对可行！
同样可用于解密SQL存储过程或者触发器。
create PROCEDURE sp_decrypt(@objectname varchar(50))
AS
begin
set nocount on
--CSDN：j9988 copyright:2004.07.15
--V3.2
--破解字节不受限制，适用于SQLSERVER2000存储过程，函数，视图，触发器
--修正上一版\"视图触发器\"不能正确解密错误
--发现有错，请E_MAIL：
begin tran
declare @objectname1 varchar(100),@orgvarbin varbinary(8000)
declare @sql1 nvarchar(4000),@sql2 varchar(8000),@sql3 nvarchar(4000),@sql4 nvarchar(4000)
DECLARE @OrigSpText1 nvarchar(4000), @OrigSpText2 nvarchar(4000) , @OrigSpText3 nvarchar(4000), @resultsp nvarchar(4000)
declare @i int,@status int,@type varchar(10),@parentid int
declare @colid int,@n int,@q int,@j int,@k int,@encrypted int,@number int
select @type=xtype,@parentid=parent_obj from sysobjects where id=object_id(@objectname)
create table #temp(number int,colid int,ctext varbinary(8000),encrypted int,status int)
insert #temp Select number,colid,ctext,encrypted,status FROM syscomments Where id = object_id(@objectname)
select @number=max(number) from #temp
set @k=0
while @k<
begin
if exists(select 1 from syscomments where id=object_id(@objectname) and )
begin
if @type='P'
set @sql1=(case when @number>1 then 'Alter PROCEDURE '+ @objectname +';'+rtrim(@k)+' WITH ENCRYPTION AS '
else 'Alter PROCEDURE '+ @objectname+' WITH ENCRYPTION AS '
end)
if @type='TR'
begin
declare @parent_obj varchar(255),@tr_parent_xtype varchar(10)
select @parent_obj=parent_obj from sysobjects where id=object_id(@objectname)
select @tr_parent_xtype=xtype from sysobjects where
if @tr_parent_xtype='V'
begin
set @sql1='Alter TRIGGER ON '+OBJECT_NAME(@parentid)+' WITH ENCRYPTION INSTERD OF Insert AS PRINT 1 '
end
else
begin
set @sql1='Alter TRIGGER ON '+OBJECT_NAME(@parentid)+' WITH ENCRYPTION FOR Insert AS PRINT 1 '
end
end
if @type='FN' or @type='TF' or @type='IF'
set @sql1=(case @type when 'TF' then
'Alter FUNCTION '+ @objectname+'(@a char(1)) returns @b table(a varchar(10)) with encryption as begin insert @b select @a return end '
when 'FN' then
'Alter FUNCTION '+ @objectname+'(@a char(1)) returns char(1) with encryption as begin return @a end'
when 'IF' then
'Alter FUNCTION '+ @objectname+'(@a char(1)) returns table with encryption as return select @a as a'
end)
if @type='V'
set @sql1='Alter VIEW WITH ENCRYPTION AS Select 1 as f'
set @q=len(@sql1)
set @sql1=@sql1+REPLICATE('-',4000-@q)
select @sql2=REPLICATE('-',8000)
set @sql3='exec(@sql1'
select @colid=max(colid) from #temp where
set @n=1
while @n<=CEILING(1.0*(@colid-1)/2) and len(@sql3)<=3996
begin
set @sql3=@sql3+'+@'
set @n=@n+1
end
set @sql3=@sql3+')'
exec sp_executesql @sql3,N'@sql1 nvarchar(4000),@ varchar(8000)',@sql1=@sql1,@=@sql2
end
set @k=@k+1
end
set @k=0
while @k<
begin
if exists(select 1 from syscomments where id=object_id(@objectname) and )
begin
select @colid=max(colid) from #temp where
set @n=1
while @n<
begin
select @OrigSpText1=ctext,@encrypted=encrypted,@status=status FROM #temp Where and